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Immediately after submitting your project (which means uploading it to the location you re given in your instructions), you should schedule your follow-up essay exam! We can t emphasize strongly enough that you should take your follow-up exam at the earliest possible moment. The fresher the project is in your mind, the easier it will be. You take the follow-up exam just as you did the Programmer s exam in a Prometric Testing Center, where you answer questions in a computer application. Rather than multiple-choice questions, however, your follow-up consists solely of essay questions. One of the main purposes of the follow-up is to see that indeed you are the one who wrote the application. So, you ll get questions related to the design and implementation decisions you had to make along the way. Once you ve completed your essay exam, the results of the essay along with your submitted project are sent to an assessor and the fun begins. Well, for the assessor anyway. You, on the other hand, have to sit there pulling your hair out until you get your results. Which could take as long as six weeks! Unlike the Programmer s exam, where the results show up instantly, before you even leave the testing center, the Developer exam is marked by a real, live (which is a good thing, we re told dead assessors have too many issues) human being. They ll use your essay questions to understand what s really happening.

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66. Let us make use of the right triangle of Fig. 64 and eqs. (69) and (70) in section 5.2, as follows.

You never know what kind of questions you re going to get. Be prepared to describe anything that you might have had to consider in your design or implementation. The following questions don t necessarily reflect the actual exam questions, but they do suggest what you need to think about when preparing. We recommend that you relax about the follow-up! You ve done the crucial work by designing and building your application, and assuming you and not your cousin Chad who owes you did the project yourself, you shouldn t have any trouble with the follow-up. Remember, there is NO ONE RIGHT ANSWER. There is, however, a wrong

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The regulator is con gured as an open-loop model in order to measure the Bode response. Inductor L2 is set to 1 H in order to effectively open the loop. The plots in Figs. 4.4, 4.5, and 4.6 show the modulator gain (VM(10)/VM(9) and VP(10) - VP(9), where VM is the magnitude and VP is the phase), the error ampli er gain (V(9)), and the overall loop gain (V(10)), respectively. In the next simulation, the loop is closed in order to simulate the audio susceptibility and load transient characteristics of the converter. The modi ed schematic is shown in Fig. 4.7. Note that L2 has been removed.

answer: the answer that contradicts the design, structure, and implementation of your application. As long as you re consistent, however, you should have nothing to fear from this part of the exam. The following questions can help you prepare for the follow-up:

First,

Describe your overall locking scheme and why you chose that approach. What design patterns did you use on this application What aspects of your design allow for future modifications Describe your threading and synchronization decisions.

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Once you ve submitted your follow-up assignment and taken your follow-up essay exam, take a deep breath, relax, and consider a refreshing alcoholic beverage. Or three. You re done! Now all that s left is the staggeringly torturous, endless, agonizingly slow, wait for the results. And after that, and after you ve recovered from the no more certifications for me no matter what you hear me say phase, you can start planning your next certification effort. In the meantime, don t count your chickens until you ve reviewed the following key points summary. And then you re done. (Well, except for re-reading the threads chapter.) (Not to mention learning the exotic subtleties of the JTable.)

b h sin with as reference angle ; b h cos with as reference angle ; thus sin cos ; or; since 90 ; sin cos 90 ; as required: Next, a h cos with as reference angle ; a h sin with as reference angle ; thus, cos sin ; or; since 90 ; cos sin 90 ; as required: 67 (a) (b) From eq (81), 360f 180,000; thus f 500 Hz; answer: By eq (81), v 100 sin 27,0008 Since 27,000=360 75 complete cycles, with zero degrees left over, we have v 100 sin 08 0; answer: 68 Here, ! 2 f 533,850, which gives (using ordinary calculator values for ) f 84,964:866 Hz; approx: Hence, by eq (91), T 1=84,964:866 1:17695 10 5 seconds 11:7695 microseconds; answer: 69 From eq (91), f 1=T.

Follow your project submission instructions perfectly. Your project will probably require you to package up all files in a single JAR. Your application should be (your instructions will confirm this) an

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